The equation whose roots are the reciprocal of the roots of the equation ax^2+bx+c is cx^2+bx+a
Roots
Roots of x^2+x+1=0 are 1,w,w^2 where 1+w+w^2=0 and w^3=1
Finding Sum of the rootsFor a cubic equation ax^3+bx^2+cx+d=o sum of the roots = - b/a sum of the product of the roots taken two at a time = c/a product of the roots = -d/a
For a biquadratic equation ax^4+bx^3+cx^2+dx+e = 0 sum of the roots = - b/a sum of the product of the roots taken three at a time = c/a sum of the product of the roots taken two at a time = -d/a product of the roots = e/a
For more study materials/ Vedic Maths tricks/ Practice tests : www.tutioncentral.com
Also visit: http://jackofinterviews.blogspot.com/
Facebook page: https://www.facebook.com/pages/TutionCentral
CAIIB/JAIIB Pages- https://www.facebook.com/pages/Tutioncentral-CAIIB-JAIIB
https://www.facebook.com/pages/IBPS-Banking-Tutioncentralcom
